CHEMICAL BONDING15Filling in the appropriate hydrogens gives the correct structures:Continue with the remaining parts of the problem using the general approach outlined forpart (a).(b)C5H12(c2H4Cl2(d4H9Br(e3H9NNote that when the three carbons and the nitrogen are arranged in a ring, the molecularformula based on such a structure is C3H7N, not C3H9N as required.1.37(a)All three carbons must be bonded together, and each one has four bonds; therefore, the mo-lecular formula C3H8uniquely corresponds to:(b)With two fewer hydrogen atoms than the preceding compound, either C3H6must containa carbon–
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