Portmess Homework Solutions 41

Portmess Homework Solutions 41 - 3 ) is not present;...

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Cyclopentane and neopentane are not isomers of these two compounds, nor are they isomers of each other. ( c ) The compounds that are isomers are cyclohexane, methylcyclopentane, and 1,1,2- trimethylcyclopropane. Hexane, CH 3 CH 2 CH 2 CH 2 CH 2 CH 3 , has the molecular formula C 6 H 14 ; it is not an isomer of the others. ( d ) The three that are isomers all have the molecular formula C 5 H 10 . Propylcyclopropane is not an isomer of the others. Its molecular formula is C 6 H 12 . ( e ) Only 4-methyltetradecane and pentadecane are isomers. Both have the molecular formula C 15 H 32 . 2.25 The oxygen and two of the carbons of C 3 H 5 ClO are part of the structural unit that characterizes epoxides. The problem speci f es that a methyl group (CH
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Unformatted text preview: 3 ) is not present; therefore, add the CH 3 (CH 2 ) 2 CH(CH 2 ) 9 CH 3 CH 3 4-Methyltetradecane C 15 H 32 CH 3 (CH 2 ) 13 CH 3 Pentadecane C 15 H 32 CH 3 CHCHCHCH(CH 2 ) 4 CH 3 CH 3 CH 3 CH 3 CH 3 2,3,4,5-Tetramethyldecane C 14 H 30 CH 3 CH 2 CH 2 CH(CH 2 ) 5 CH 3 4-Cyclobutyldecane C 14 H 28 CH 2 CH 2 CH 3 1,1-Dimethylcyclopropane C 5 H 10 Ethylcyclopropane C 5 H 10 Cyclopentane C 5 H 10 CH 3 CH 3 CH 2 CH 3 Methylcyclopentane C 6 H 12 CH 3 1,1,2-Trimethylcyclopropane C 6 H 12 CH 3 CH 3 H 3 C Cyclohexane C 6 H 12 Cyclopentane C 5 H 10 Neopentane C 5 H 12 CH 3 CCH 3 CH 3 CH 3 ALKANES 35...
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This note was uploaded on 09/20/2011 for the course CHM 2210 taught by Professor Reynolds during the Fall '01 term at University of Florida.

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