Equations (1) and (2) are the combustion of hydrogen and acetylene, respectively. Equation (3)is the reverse of the combustion of ethylene, and its value of DH°is the negative of the heatof combustion of ethylene.The value of DH°for the hydrogenation of acetylene to ethane is equal to the sum of thetwo reactions just calculated:(c)We use the equations for the combustion of ethane, ethylene, and acetylene as shown.The value of DH°for reaction (1) is twice that for the combustion of ethylene because 2 molof ethylene are involved.2.37(a)The hydrogen content increases in going from CH3C>CH to CH3CH?CH2. The organiccompound CH3C>CH is reduced.(b)Oxidationoccurs because a CGO bond has replaced a CGH bond in going from startingmaterial to product.(c)There are two carbon–oxygen bonds in the starting material and four carbon–oxygen bonds inthe products. Oxidationoccurs.(d)Although the oxidation state of carbon is unchanged in the processoverall, reductionof the organic compound has occurred. Its hydrogen content has increasedand its oxygen content has decreased.2.38In the reaction
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This note was uploaded on 09/20/2011 for the course CHM 2210 taught by Professor Reynolds during the Fall '01 term at University of Florida.