Portmess Homework Q&S 61

Portmess Homework Q&S 61 - 55 CONFORMATIONS OF ALKANES...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
3.26 ( a ) Three isomers of C 5 H 8 contain two rings and have no alkyl substituents: ( b ) Five isomers of C 6 H 10 contain two rings and have no alkyl substituents: 3.27 ( a ) The heat of combustion is highest for the hydrocarbon with the greatest number of carbons. Thus, cyclopropane, even though it is more strained than cyclobutane or cyclopentane, has the lowest heat of combustion. A comparison of heats of combustion can only be used to assess relative stability when the compounds are isomers. ( b ) All these compounds have the molecular formula C 7 H 14 . They are isomers, and so the one with the most strain will have the highest heat of combustion. H 3 CC H 3 CH 3 H 3 C 1,1,2,2-Tetramethylcyclopropane (high in angle strain; bonds are eclipsed; van der Waals strain between cis methyl groups) Heat of combustion
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 09/20/2011 for the course CHM 2210 taught by Professor Reynolds during the Spring '01 term at University of Florida.

Ask a homework question - tutors are online