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Tutorial_8

# Tutorial_8 - ¹ ¸ E9 =1(2/\$B\$1^2 2/\$B\$2^2(F9 D9/\$B\$1^2(E8...

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Tutorial 8 A long rectangular bar of cross-section 12 cm by 8 cm is subjected to the thermal boundary conditions indicated in the sketch below. The ceramic rod has a thermal conductivity of g1863=1 g1849g1865 g2879g2869 g1837 g2879g2869 . Assuming there is no temperature variation in the g1878 direction, predict the steady-state temperature distribution in the bar cross- section, g1846=g1846g4666g1876,g1877g4667 , using a finite difference scheme with Δg1876=3 cm and Δg1877=2 cm . g1877 g1876 (1) Insulated (3) g1846=0℃ (ice) (4) Cold air flow at g1846 g3002 =5℃ , h = 1 Wm -2 K -1 g1869 g2868 =10 g1849 g1865 g2870

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Unformatted text preview: ¹ ¸ E9 =1/(2/\$B\$1^2+2/\$B\$2^2)*((F9+D9)/\$B\$1^2+(E8+E10)/\$B\$2^2), copy over and down to G11 D9 =E9, copy down to D11 E8 =1/(\$B\$3+\$B\$4/\$B\$2)*(\$B\$4/\$B\$2*E9+\$B\$3*\$B\$6), copy over to G8 E12 =E11+\$B\$5*\$B\$2/\$B\$4, copy over to G12 H9 = 0, copy down to H11 A B C D E F G H 1 dx = 0.03 m 2 dy = 0.02 m 3 h = 1 W/m^2-K 4 k = 1 W/m-K 5 q0 = 10 W/m^2 6 TA = 5 C 7 8 8 1.279 1.081 0.686 9 6 1.204 1.204 1.002 0.600 0.000 10 4 1.219 1.219 1.013 0.601 0.000 11 2 1.326 1.326 1.116 0.687 0.000 12 0 1.526 1.316 0.887 13 y [cm] 14 x [cm] 0 3 6 9 12...
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Tutorial_8 - ¹ ¸ E9 =1(2/\$B\$1^2 2/\$B\$2^2(F9 D9/\$B\$1^2(E8...

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