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q1p302key

# q1p302key - CH302 TA Practice Quiz 1 Answer Key 1 An...

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CH302 TA Practice Quiz 1 Answer Key 1. An unknown liquid is 2000 Pa at 25 oC and 7500 Pa at 50 oC. Based on the Clausius- Clapeyron equation which expression below could be used to solve for the enthalpy of vaporization ( Δ H vap ) of the unknown liquid? 1. [(8.314 J/mol*K)ln(7500 Pa /2000 Pa)] / [(1/50) – (1/25)] = Δ H vap 2. -[(8.314 J/mol*K)ln(7500 Pa /2000 Pa)] / [(1/323) – (1/298)] = Δ H vap 3. [(8.314 J/mol*K)ln(7500 Pa /2000 Pa)] / [(1/323) – (1/298)] = Δ H vap 4. -[(8.314 J/mol*K)ln(7500 Pa /2000 Pa)] / [(1/50) – (1/25)] = Δ H vap 5. -[(8.314 J/mol*K)ln(7500 Pa /2000 Pa)] / [(1/323) + (1/298)] = Δ H vap Explanation: Solve the Clausius-Clapeyron equation to express Δ Hvap in terms of the other variables. Plug in the given values, but remember to convert temperature to Kelvin. 2. Sketch a phase diagram using the following information: triple point at 45 atm and 310 K. Critical point at 65 atm and 575 K. The diagram intersects the Y axis at 5 atm. Y axis: 0 to 70 atm. X-axis: 0 to 600 K. Which of the following would result in sublimation? 1. at 250 K, increasing the pressure from 10 atm to 50 atm.

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q1p302key - CH302 TA Practice Quiz 1 Answer Key 1 An...

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