# q1ps302 - CH302 TA Practice Quiz 1 1. An unknown liquid is...

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CH302 TA Practice Quiz 1 1. An unknown liquid is 2000 Pa at 25 oC and 7500 Pa at 50 oC. Based on the Clausius- Clapeyron equation which expression below could be used to solve for the enthalpy of vaporization ( Δ H vap ) of the unknown liquid? 1. [(8.314 J/mol*K)ln(7500 Pa /2000 Pa)] / [(1/50) – (1/25)] = Δ H vap 2. -[(8.314 J/mol*K)ln(7500 Pa /2000 Pa)] / [(1/323) – (1/298)] = Δ H vap 3. [(8.314 J/mol*K)ln(7500 Pa /2000 Pa)] / [(1/323) – (1/298)] = Δ H vap 4. -[(8.314 J/mol*K)ln(7500 Pa /2000 Pa)] / [(1/50) – (1/25)] = Δ H vap 5. -[(8.314 J/mol*K)ln(7500 Pa /2000 Pa)] / [(1/323) + (1/298)] = Δ H vap 2. Sketch a phase diagram using the following information: triple point at 45 atm and 310 K. Critical point at 65 atm and 575 K. The diagram intersects the Y axis at 5 atm. Y axis: 0 to 70 atm. X-axis: 0 to 600 K. Which of the following would result in sublimation? 1. at 250 K, increasing the pressure from 10 atm to 50 atm. 2. at 400 K, increasing the pressure from 20 atm to 60 atm.

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## This note was uploaded on 09/17/2011 for the course CH 302 taught by Professor Holcombe during the Spring '07 term at University of Texas at Austin.

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q1ps302 - CH302 TA Practice Quiz 1 1. An unknown liquid is...

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