Quiz 5 Spring 2011 - Version 281 – Quiz 5 – laude –(51635 1 This print-out should have 8 questions Multiple-choice questions may continue on

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Unformatted text preview: Version 281 – Quiz 5 – laude – (51635) 1 This print-out should have 8 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 5.0 points Consider the half reactions below: Br 2 + 2 e −-→ 2 Br − Fe 3+ + 3 e −-→ Fe Co 3+ + e −-→ Co 2+ Zn 2+ + 2 e −-→ Zn E ◦ = +1 . 07 E ◦ =- . 04 E ◦ = +1 . 80 E ◦ =- . 76 Which species is the strongest oxidizing agent? 1. Zn 2. Co 3+ correct 3. Br 2 4. Fe Explanation: The right hand side of the half reaction with the highest standard reduction potential is the strongest oxidizing agent. In this case, that species is Co 3+ . 002 5.0 points Consider a voltaic cell based on the redox reaction Zn + Cl 2 → ZnCl 2 . The half cell reaction occuring at the anode is 1. Zn → Zn 2+ + 2 e − correct 2. None of these 3. Cl 2 + 2 e − → 2 Cl − 4. Zn 2+ + 2 Cl − → ZnCl 2 Explanation: Oxidation (loss or production of e − ) always occurs at the anode. 003 5.0 points Balance the net ionic equation MnO − 4 + I − → I 2 + MnO 2 (basic solution). What is the sum of the coefficients?...
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This note was uploaded on 09/17/2011 for the course CH 302 taught by Professor Holcombe during the Spring '07 term at University of Texas at Austin.

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Quiz 5 Spring 2011 - Version 281 – Quiz 5 – laude –(51635 1 This print-out should have 8 questions Multiple-choice questions may continue on

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