{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

hw7 - lakha(ml29327 HW#7 Jaafari(1444 This print-out should...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
lakha (ml29327) – HW#7 – Jaafari – (1444) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points The alternating voltage of a generator is rep- resented by the equation E = E 0 sin ω t , where E is in volts, E 0 = 313 V, ω = 295 rad / s, and t is in seconds. Find the frequency of the electric potential E . Correct answer: 46 . 9507 Hz. Explanation: Let : E max = E 0 = 313 V , and ω = 295 rad / s . ω = 2 π f f = ω 2 π = 295 rad / s 2 π = 46 . 9507 Hz . 002 (part 2 of 2) 10.0 points Find the voltage output of the source. Correct answer: 221 . 324 V. Explanation: The rms voltage is E rms = E max 2 = 313 V 2 = 221 . 324 V . 003 (part 1 of 2) 10.0 points The alternating potential difference of a gen- erator is represented by the equation E = (312 V) sin(355 rad / s) t , where E is in volts and t is in seconds. Find the frequency of the potential differ- ence of the source. Correct answer: 56 . 5 Hz. Explanation: Let : E = V max sin ω t = (312 V) sin(355 rad / s) t , and ω = 2 π f = 355 rad / s .
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern