hw8 - lakha(ml29327 HW#8 Jaafari(1444 This print-out should...

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lakha (ml29327) – HW#8 – Jaafari – (1444) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page – Fnd all choices before answering. 001 (part 1 of 2) 10.0 points A battery with an emf of 13 . 9 V and internal resistance of 0 . 45 Ω is connected across a load resistor R . If the current in the circuit is 0 . 85 A, what is the value of R ? Correct answer: 15 . 9029 Ω. Explanation: Let : E = 13 . 9 V , I = 0 . 85 A , and R i = 0 . 45 Ω . The electromotive force E is given by E = I ( R + R i ) R = E I - R i = 13 . 9 V 0 . 85 A - 0 . 45 Ω = 15 . 9029 Ω . 002 (part 2 of 2) 10.0 points What power is dissipated in the internal re- sistance of the battery? Correct answer: 0 . 325125 W. Explanation: The power dissipation due to the internal resistance is P = I 2 R i = (0 . 85 A) 2 (0 . 45 Ω) = 0 . 325125 W . 003 (part 1 of 2) 10.0 points i C R S V Consider the following statements. A1: I = 0 A2: I = V R A3: I = V R e - 1 / ( RC ) B1: V C = 0 B2: V C = V B3: V C = V e - 1 / ( RC ) Immediately after the switch is closed, the current, I through R, and the potential across the capacitor, V C , are respectively given by 1. A3, B2 2. A2, B2 3. A2, B1 correct 4. A1, B2 5. A3, B3 6. A3, B1 7. A2, B3 8. A1, B1 9. A1, B3 Explanation:
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This note was uploaded on 09/17/2011 for the course PHYS 1401 taught by Professor Violaruck during the Fall '07 term at Dallas Colleges.

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hw8 - lakha(ml29327 HW#8 Jaafari(1444 This print-out should...

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