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Assignment 2 solutions

# Assignment 2 solutions - CE93-Engineering Data Analysis...

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CE93-Engineering Data Analysis Mark Hansen, Fall 2009 CE93 Homework 2 – Solution 1. Sample median and mean values. > median(x), mean(x), median(y), mean(y) Data Median Mean Density 2445 2444.9 Strength 60.10 60.14 These measures fall in the central regions of the corresponding normalized frequency diagrams as shown in the following figures. Mean=median=2445 mean=median=60.1 2. Range, IQR, Mean absolute deviations, d , the sample (unbiased) variance, s 2 , the sample (unbiased) standard deviations, s and the sample c.o.v.’s d ˆ . >> range(x), IQR(x), mad(x), var(x), std(x), std(x)/mean(x), std(x,1) >> range(y), IQR(y), mad(y), var(y), std(y), std(y)/mean(y), std(y,1) Data Range IQR d s 2 s g2012 g4632 s normalized by N Density 77 19 12.2 255.8 16.0 0.0065 15.8 Strength 19.6 6.55 3.84 25.15 5.01 0.0834 4.95 The estimate of the standard deviation when normalized by N is slightly smaller than the unbiased estimate. The strength data has higher dispersion since it has a larger sample c.o.v. 3. Sample size

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CE93-Engineering Data Analysis Mark Hansen, Fall 2009 Answers: >> f10=E1_2(1:10,2); I expect (through inspection) that the mean will be about 60. I expect the median to be about 61.5.
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Assignment 2 solutions - CE93-Engineering Data Analysis...

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