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Unformatted text preview: CE93Engineering Data Analysis Mark Hansen, Fall 2009 Assignment 9 (Mock Midterm) Solutions Question 1 a) b) Either representation (solid or dotted line) will be fine for full points. c) Note: the outlier at 5 represents 5 data points 25 th percentile: 2 50 th percentile: 2 75 th percentile: 3 IQR=32=1 Tails are 1.5*IQR. Note that we are dealing with discrete r.v. if upper tail extends to 3+1.5=4.5, this tail INCLUDES occupancy=4 but does NOT include observations of occupancy =5. 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 1 2 3 4 5 6 CE93Engineering Data Analysis Mark Hansen, Fall 2009 d) Median is where g G = 0.5 . = 2 e) Var(X)=E(X 2 )(EX) 2 Can also calculate variance as = u = 0.988 Or the sample variance = u = 0.998 f) The skewness is positive. There are more possible values of occupancy to the right of the expected value. The box and whiskers plot shows outliers (occupancy=5) outliers in the right tail of the distribution. CE93Engineering Data Analysis Mark Hansen, Fall 2009 Question 2 Question 3 d) E(X)=0*0.4+1*0.6=0.6 e) g G ? Prove by counterexample Test: if they are independent, then = 0, = 1 == = 0 = 1 0.1 0.4 0.30....
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This note was uploaded on 09/19/2011 for the course CE 93 taught by Professor Hansen during the Fall '10 term at University of California, Berkeley.
 Fall '10
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