{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

math54 - quiz 3 - solns

# math54 - quiz 3 - solns - ±-1 4 1 8 1 8 3 16 ² 3 Mark the...

This preview shows pages 1–2. Sign up to view the full content.

Math 54 quiz 3 Solutions 1. (4 points) Calculate the determinant, using any method you like 1 0 0 1 0 1 0 1 0 1 1 0 0 1 1 1 Let’s use cofactor expansion along the first column. This gives (+1) det 1 0 1 1 1 0 1 1 1 as the only term. Next we can use the algorithm for 3 × 3 matrices to obtain 1 + 0 + 1 - 1 - 0 - 0 = 1 . 2. (3 points) Find the inverse of the matrix A below. (Again any method is fine) -3 2 2 4 We will row reduce the matrix below -3 2 1 0 2 4 0 1 1 10 1 2 2 4 0 1 1 10 1 2 0 -16 -2 -3 1 10 1 2 0 1 2 16 3 16

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
1 0 - 1 4 1 8 0 1 1 8 3 16 So, we obtain -
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ±-1 4 1 8 1 8 3 16 ² 3. Mark the following as true or false. No justiﬁcation is needed. (1 pt each) (a) If A is a square matrix, and A x = b has a unique solution for some b, then det A 6 = 0. TRUE (b) The matrix 1 1-1 2 1-2 1 3 1-3 4 1-4 1 is invertible. FALSE (c) If A and B are square matrices of the same size, det AB = det BA . TRUE...
View Full Document

{[ snackBarMessage ]}