BUS 306 Module 2 Case Assignment

BUS 306 Module 2 Case Assignment - Graph P = 140n - 8500...

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Functions Robert J. Blair Trident University International BUS 306 Module 2 Case Assignment Dr. Auden 6 Aug 2011 Functions 1. Evaluate the function f(x) = 9x - 6 for x=0. f(0) = 9(0) - 6 = -6 2. Bob owns a watch repair shop. He has found that the cost of operating his shop is given by C(x) = 4x2- 296x+85 , where c is cost and x is the number of watches repaired. How many watches must he repair to have the lowest cost? y = ax2 + bx + c C(x) = 4x2 +-296x+85 a=4 b=-296 X= -(b/2a) = -[-296/(2*4)] = 296/8 = 37 watches 3. Find the slope of the line through the points ( 5, -5) and ( 6, -1) M=rise/run=change in y/change in x=y2-y1/x2-x1 M= -1-(-5)/6-5=-1+5/6-5=4/1= 4 4. Kafka Inc. imports hard drives and sells them on the internet. The profit is given by the equation P = 140n - 8500, where n is the number of hard drives sold.
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Unformatted text preview: Graph P = 140n - 8500 for n < 1000. Estimate the profit, to the nearest ten dollars, corresponding to the sale of 875 hard drives. = $114,000 profit P= 140n-8500 n=1000 P= 140n-8500 n=875 P= 140n-8500 n=1000 P=(140*0)-8500 P=(140*875)-8500 P=(140*1000)-8500 P= 0-8500 P= 122500-8500 P= 140000-8500 P= -$8500 P= $114,000 P= $131,500 [pic] 5. When $ 8500 is invested in a savings account paying simple interest for the year, the interest, i in dollars, can be obtained from the equation i = 8500r , where r is the rate of interest in decimal form. Graph i = 8500r , for r up to and including a rate of 16%. If the rate is 12%, how much interest is earned? = $1020 i=8500r r=0% or 0.0 i=8500r r=12% or 0.12 i=8500r r=16% or 0.16 i=8500*0 i=8500*0.12 i=8500*0.16 i=0 i=1020 i=1360 [pic]...
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BUS 306 Module 2 Case Assignment - Graph P = 140n - 8500...

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