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# 9.69 - Problem 9.69 The masses of the blocks are m,‘ = 30...

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Unformatted text preview: Problem 9.69 The masses of the blocks are m,‘ = 30 kg and My = 70 kg. Between all of the contacting surfaces, #5 = 0.1. What is the largest force F that can be applied without causing the blocks to siip? Solution: The equilibrium equations for block A are 2P“. : R — lv'sinﬁif’ + {if cos 2t)" — Psin 20° 2 U. 2F, : ”JR — F cos 30‘= m In“: + Pros 30“ + mi“ cos 20“ = i}. The equilibrium equations for block 3 on: SF. :Psinlt)" —j1‘i-PCUSZUU m mN : U. ZFX : it'cos 20” — mPsinlO" - mgg + N : 0. Substituting the given values and solving yields R2212 N.P:45() N, N 21130 N. {lild F m [97 N. @) 2003 Pearson Education. Inc, Upper Saddle River. NJ. All rights a'csurvcd. This material is protected under all copyright laws “5.1:“? currently cxtsl. No portion ol lillS malarial may hi: reproduced, in any lorm or by any means, Without [icrinission in erllllg from [111. pnhitst .- 730 ...
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