4-58 - = F= F eF 200lbs 3 ft 5 ft 0 ft 6 ft 4 ft 1 ft = 3...

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( ) ( ) ( ) ( ) ( ) 2 22 3 5 ,0 6 ,4 1 200 200 2, 6,3 7 35 06 41 400 1200 600 ,, 7 77 F ft ft ft ft ft ft lbs F F e lbs ft ft ft ft ft ft ft ft lbs −−− = = = −− +− =  ( ) ( ) ( ) ( ) ( ) ( ) ˆ ˆˆ 5 61 400 1200 600 7 600 1200 600 400 1200 400 ˆ 6 15 1 5 6 () 7 7 7 7 A i jk M AB F ft ft ft lbs lbs lbs i j k ft lbs = ×=  = +   
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This note was uploaded on 09/18/2011 for the course ENGR 200 taught by Professor Mullen during the Spring '08 term at Case Western.

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