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Unformatted text preview: 1| . Then show that if x N 1 where you can choose your own , | z | has a maximum value on this neighbourhood.) (b) Show that the following limit does not exist by showing that the expression takes on different values for x and x . lim x x | x | x (c) Evaluate the following limit by simplifying the expression to an expression whose limit you know. lim x 1 x 2 x x 2 3 x 4 Also evaluate this limit as x . 3.(a) Where are the discontinuities of the following function? Explain your answers. f x x 1 x 2 1 when x 2 1 f x when x 2 1 (b) What number a will make the following function continuous? f x 5 x 1 when x 2 f x ax 2 1 when x 2...
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- Spring '06