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Unformatted text preview: 1 Physics 208N-004 Lecture #9 31 January 2011 Electric Fields 23-4 through 23-8 Review: 1. E-Field is due to force exerted on a tiny positive charge E = F /q 2. Electric Flux 3. Gausss Law Which applies in more situations, Gausss law or Coulombs law? Electric Potential V a = U a /q V ba = V = (U b U a )/q = -W ba /q U = qV ba U b U a = - F d l V b V a = - E dl V ba = - Ed (plate capacitor) 23-4 Potential Due to Any Charge Distribution The potential due to an arbitrary charge distribution can be expressed as a sum or integral (if the distribution is continuous): or 23-4 Potential Due to Any Charge Distribution Example 23-8: Potential due to a ring of charge. A thin circular ring of radius R has a uniformly distributed charge Q . Determine the electric potential at a point P on the axis of the ring a distance x from its center. 2 23-4 Potential Due to Any Charge Distribution Example 23-9: Potential due to a charged disk....
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This note was uploaded on 09/18/2011 for the course PY 208M 87878 taught by Professor George during the Spring '09 term at N.C. State.
- Spring '09