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Unformatted text preview: 1 Physics 208N004 Lecture #9 – 31 January 2011 Electric Fields – 234 through 238 Review: 1. EField is due to force exerted on a tiny positive charge E = F /q 2. Electric Flux 3. Gauss’s Law Which applies in more situations, Gauss’s law or Coulomb’s law? Electric Potential V a = U a /q V ba = Δ V = (U b – U a )/q = W ba /q Δ U = qV ba U b –U a =  ∫ F ● d l V b –V a =  ∫ E ● dl V ba =  Ed (plate capacitor) 234 Potential Due to Any Charge Distribution The potential due to an arbitrary charge distribution can be expressed as a sum or integral (if the distribution is continuous): or 234 Potential Due to Any Charge Distribution Example 238: Potential due to a ring of charge. A thin circular ring of radius R has a uniformly distributed charge Q . Determine the electric potential at a point P on the axis of the ring a distance x from its center. 2 234 Potential Due to Any Charge Distribution Example 239: Potential due to a charged disk....
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 Spring '09
 GEORGE
 Electrostatics, Potential Energy, Magnetic Field, Electric charge, Equipotential surfaces

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