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Unformatted text preview: on its plates is proportional to the voltage: The quantity C is called the capacitance. Unit of capacitance: the farad ( F ): 1 F = 1 C/V. 24-1 Capacitors 24-2 Determination of Capacitance For a parallel-plate capacitor as shown, the field between the plates is E = Q / ε A. Integrating along a path between the plates gives the potential difference: V ba = Qd / ε A. This gives the capacitance: 24-2 Determination of Capacitance Example 24-1: Capacitor calculations. (a) Calculate the capacitance of a parallel-plate capacitor whose plates are 20 cm × 3.0 cm and are separated by a 1.0-mm air gap. (b) What is the charge on each plate if a 12-V battery is connected across the two plates? (c) What is the electric field between the plates? (d) Estimate the area of the plates needed to achieve a capacitance of 1 F, given the same air gap d ....
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This note was uploaded on 09/18/2011 for the course PY 208M 87878 taught by Professor George during the Spring '09 term at N.C. State.
- Spring '09