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ansG1 (1)

# ansG1 (1) - Module G1 Solution to problem 1(a 29 29 29 29...

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Unformatted text preview: Module G1 Solution to problem 1 (a) ( 29 ( 29 ( 29 ( 29 ( 29 MVar X V X E V Q V V j j jX I V E A I A I V P I V P pf MW P kV kV V s t s f t out s a t f a a t a t t 48 . 37 3 cos 3 759 . 2 17990 866 5 . 17969 9 . 87 . 36 8 . 1202 10 32 . 17 87 . 36 8 . 1202 8 . 1202 8 . 10 32 . 17 3 10 50 cos 3 cos 3 87 . 36 cos 8 . 50 32 . 17 3 30 2 3 3 6 =- ⋅ = ° ∠ = + = ⋅ °- ∠ + ° ∠ × = + = °- ∠ = ⇒ = = ⋅ × × = ⋅ = = ° = ⇒ = = = = = δ θ θ θ θ (b) ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 MVar Q M P MW P out out out 38 . 38 38 . 1 cos 9 . 10 99 . 17 10 32 . 17 3 38 . 1 0241 . sin sin 9 . 17990 10 32 . 17 3 25 25 3 3 1 3 = ° × × = ° = = ⇒ × = = ⇒ =- δ δ (c) Need to find new angle : ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 MVar Q X E V P out s f t 874 . 178 9 . 10 32 . 17 3 48 . 3 cos 9 . 248 , 14 10 32 . 17 3 48 . 3 060 . 14248 10 32 . 17 3 9 . 10 50 sin 3 2 3 3 3 6- = ×- ⋅ × ⋅ = ° = ⇒ = × ⋅ × ⇒ = δ δ Solution to problem 2 (a) ( 29 rpm p f N s 1200 6 60 120 120 = = = (b) lagging V E X V E MW MW P kV k V kV k E t f s t f t f ⇒ ° = × × × × × = = = = = = = =- δ δ...
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ansG1 (1) - Module G1 Solution to problem 1(a 29 29 29 29...

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