problem02_48 solution

University Physics with Modern Physics with Mastering Physics (11th Edition)

  • Homework Help
  • PresidentHackerCaribou10582
  • 1

Info icon This preview shows page 1. Sign up to view the full content.

2.48: a) From Eq. (2.8), solving for t gives (40.0 s m – 20.0 s m )/9.80 2 s m = 2.04 s. b) Again from Eq. (2.8), . s 12 . 6 s m 80 . 9 ) s m 0 . 20 ( s m 0 . 40 2 = - - c) The displacement will be zero when the ball has returned to its original vertical position, with velocity opposite to the original velocity. From Eq. (2.8),
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: . s 16 . 8 s m 80 . 9 ) s m 40 ( s m 40 2 =--(This ignores the t = 0 solution.) d) Again from Eq. (2.8), (40 s m )/(9.80 2 s m ) = 4.08 s. This is, of course, half the time found in part (c). e) 9.80 2 s m , down, in all cases. f)...
View Full Document

  • '
  • NoProfessor
  • Velocity, Position, Displacement, 9.80 m, Interstate 40, original vertical position

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern