problem02_48 solution

# University Physics with Modern Physics with Mastering Physics (11th Edition)

• Homework Help
• PresidentHackerCaribou10582
• 1

This preview shows page 1. Sign up to view the full content.

2.48: a) From Eq. (2.8), solving for t gives (40.0 s m – 20.0 s m )/9.80 2 s m = 2.04 s. b) Again from Eq. (2.8), . s 12 . 6 s m 80 . 9 ) s m 0 . 20 ( s m 0 . 40 2 = - - c) The displacement will be zero when the ball has returned to its original vertical position, with velocity opposite to the original velocity. From Eq. (2.8),
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: . s 16 . 8 s m 80 . 9 ) s m 40 ( s m 40 2 =--(This ignores the t = 0 solution.) d) Again from Eq. (2.8), (40 s m )/(9.80 2 s m ) = 4.08 s. This is, of course, half the time found in part (c). e) 9.80 2 s m , down, in all cases. f)...
View Full Document

• '
• NoProfessor
• Velocity, Position, Displacement, 9.80 m, Interstate 40, original vertical position

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern