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Balancing Reactions - video-solutions

Balancing Reactions - video-solutions - nanni(arn437...

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nanni (arn437) – Balancing Reactions - video – CNS – (87654) 1 This print-out should have 3 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0points Balance the equation ? C 4 H 10 (g)+? O 2 (g) ? CO 2 (g)+? H 2 O(g) . using the smallest possible integers. The co- efficients are 1. 2; 13; 8; 10. correct 2. 3; 13; 12; 1. 3. 1; 13; 4; 5. 4. 1; 6; 4; 5. Explanation: A balanced equation must have the same number of each kind of atom on both sides of the equation. Since oxygen is in both products, we will leave it to be balanced last. Start either with carbon or hydrogen. There are 4 C and 10 H on the left. There are 1 C and 2 H on the right. Adding a 4 in front of CO 2 and a 5 in front of H 2 O will balance C and H: C 4 H 10 (g) + O 2 (g) 4 CO 2 (g) + 5 H 2 O(g) Now oxygen needs to be balanced. There are 2 O on the left and 13 O on the right. Adding 13 2 to O 2 will give us 13 O on the left, but we want the coefficients to be integers.
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