Unformatted text preview: V 1 . 1 is one sixth oF 6. Boyle’s law: P 1 V 1 = P 2 V 2 P 2 = P 1 V 1 V 2 = (17 psi) (6) 1 = 102 psi 002 10.0 points IF the volume is 40 mL at 190 torr, fnd the volume at 1.00 atm. Assume the temperature and amount oF gas remain constant. Correct answer: 10 mL. Explanation: P 1 = 190 torr P 2 = 1 atm = 760 torr V 1 = 40 mL Boyle’s law relates the volume and pressure oF a sample oF gas: P 1 V 1 = P 2 V 2 V 2 = P 1 V 1 P 2 = (190 torr) (40 mL) 760 torr = 10 mL...
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This note was uploaded on 09/19/2011 for the course CH 301 taught by Professor Fakhreddine/lyon during the Fall '07 term at University of Texas.
 Fall '07
 Fakhreddine/Lyon

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