LM 03 Charles' Law-solutions

LM 03 Charles' Law-solutions - ◦ C 002 10.0 points A...

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nanni (arn437) – LM 03 Charles’ Law – vanden bout – (50985) 1 This print-out should have 2 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 10.0 points A gas at 57 C occupies 4 . 04 L. At what tem- perature will the volume be 3 . 13 L, assuming the same pressure? Correct answer: - 17 . 3655 C. Explanation: V 1 = 4 . 04 L V 2 = 3 . 13 L T 1 = 57 C + 273 . 15 = 330 . 15 K T 2 = ? V 1 T 1 = V 2 T 2 T 2 = T 1 V 2 V 1 = (330 . 15 K) (3 . 13 L) 4 . 04 L = 255 . 785 K C = K - 273 . 15 = - 17 . 3655
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Unformatted text preview: ◦ C 002 10.0 points A sample oF a gas occupies 770 mL at 15 ◦ C and 740 torr. What volume would it occupy at the same pressure and 352 ◦ C? Correct answer: 1671 mL. Explanation: T 1 = 15 ◦ C + 273 = 288 K V 1 = 770 mL T 2 = 352 ◦ C + 273 = 625 K Charles’ law relates the volume and abso-lute (Kelvin) temperature oF a sample oF gas: V 1 T 1 = V 2 T 2 V 2 = V 1 T 2 T 1 = (770 mL) (625 K) 288 K = 1671 mL...
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This note was uploaded on 09/19/2011 for the course CH 301 taught by Professor Fakhreddine/lyon during the Fall '07 term at University of Texas.

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