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Unformatted text preview: Cl – Na + Sodium metal Chlorine gas 11e – 11p + 12n Sodium atom (Na) Loses electron Chloride ion (Cl – ) e – 17p + 18n 17e – Chlorine atom (Cl) 17p + 18n Gains electron 18e – Sodium ion (Na + ) 10e – 11p + 12n A The elements (lab view) C Electron transfer B The elements (atomic view) E The compound (lab view): sodium chloride crystal D The compound (atomic view): Na + and Cl – in the crystal NaCl Elements sodium and chlorine reacting to form an ionic compound Dissolving Compounds...
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This note was uploaded on 09/19/2011 for the course CHEM 51423 taught by Professor Martinovic during the Spring '10 term at Skyline College.
- Spring '10