assiganment1solution

# assiganment1solution - MAT 1339 C Assignment 1 (Due Wed....

This preview shows pages 1–3. Sign up to view the full content.

MAT 1339C Assignment 1 (Due Wed. Sept. 29th, 5:30 pm) Student Number : Name: Problem 1: [1 mark] Using the deﬁnition of a derivative ﬁnd f 0 ( x ) if f ( x ) = x 3 - 2 x + 2010. Solution: f 0 ( x ) = lim h 0 f ( x + h ) - f ( x ) h = lim h 0 ( x + h ) 3 - 2( x + h ) + 2010 - ( x 3 - 2 x + 2010) h = lim h 0 (3 xh + 3 x 2 + h 2 - 2) h h = lim h 0 3 xh + 3 x 2 + h 2 - 2 = 3 x 2 - 2 . Problem 2: [1 mark] Using the rules of diﬀerentiation ﬁnd the derivative of g ( x ) = 2 x 2010 - 1 2 x 2000 + 10 x 6 . Solution: f 0 ( x ) = (2 x 2010 ) 0 - ( 1 2 x 2000 ) 0 + ( 10 x 6 ) 0 = 2 · 2010 · x 2010 - 1 - 1 2 · 2000 · x 2000 - 1 + 10 · ( - 6) · x - 6 - 1 = 4020 x 2009 - 1000 x 1999 - 60 x 7 .

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Problem 3: [1 mark] If g ( x ) = 2 x 6 - 12 x 3 and f ( x ) = 12 x 3 + 4 x 4 ﬁnd the derivative of f ( x ) g ( x ) . Solution: f ( x ) g ( x ) · 0 = 12 x 3 + 4 x 4 2 x 6 - 12 x 3 · 0 = (12 + 4 x ) x 3 (2 x 3 - 12) x 3 · 0 = 12 + 4 x 2 x 3 - 12 · 0 = (12 + 4 x ) 0 (2 x 3 - 12) - (12 + 4 x )(2 x 3 - 12) 0 (2 x 3 - 12) 2 = 4(2
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 09/20/2011 for the course SCIENCE MAT1330 taught by Professor Rad during the Spring '11 term at University of Ottawa.

### Page1 / 5

assiganment1solution - MAT 1339 C Assignment 1 (Due Wed....

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online