problem02_50 solution

University Physics with Modern Physics with Mastering Physics (11th Edition)

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2.50: a) From Eq. (2.15), the velocity v 2 at time t + = t t dt αt v v 1 1 2 ) ( 2 2 1 2 1 t t v - + = α 2 2 1 1 2 2 t t v + - = = (5.0 s m ) – (0.6 3 s m )(1.0 s) 2 + (0.6 3 s m ) t 2 = (4.40 s m ) + (0.6 3 s m ) t 2 . At t 2 = 2.0 s, the velocity is v 2 = (4.40 s m ) + (0.6 3 s m )(2.0 s) 2 = 6.80 m/s, or 6.8 s m to two significant figures. b) From Eq. (2.16), the position x 2 as a function of time is dt v x x x t t 1 1 2 + = dt t t t ) ) s / m 6 . 0 ( ) s /
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problem02_50 solution - 2.50: a) From Eq. (2.15), the...

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