This preview shows page 1. Sign up to view the full content.
Unformatted text preview: (1) Find the 95% conﬁdence interval of p . What is the margin of error? Find the 90% conﬁdence interval of p . A: ˆ p = 180 / 1000 = . 18, s = p ˆ p (1ˆ p ) /n = . 012. The 95% CI is [ˆ p2 s, ˆ p + 2 s ] = [ . 156 ,. 204]. The margin of error is 2 s = . 024. The 90% CI is [ˆ p1 . 64 s, ˆ p + 1 . 64 s ] = [ . 160 ,. 200]. (2) Test the hypothesis H : p = 1 / 6 versus the hypothesis H 1 : p > 1 / 6. Calculate the pvalue. Is there evidence that the die is not fair? A: The observed value of ˆ p is 180 / 1000 = . 18. The Zscore is (ˆ pp ) / p p (1p ) /n = ( . 181 / 6) / p 1 / 6 × (11 / 6) / 1000 = 1 . 1314. The pvalue is Pr( Z ≥ 1 . 1314) = . 129. There is no much evidence against H . 1...
View
Full
Document
This note was uploaded on 09/20/2011 for the course STAT 100B taught by Professor Wu during the Spring '11 term at UCLA.
 Spring '11
 Wu
 Bernoulli, Variance

Click to edit the document details