6.2-solutions

# 6.2-solutions - tran(pt4954 – 6.2 – campisi –(54970 1...

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Unformatted text preview: tran (pt4954) – 6.2 – campisi – (54970) 1 This print-out should have 5 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points Find the volume, V , of the solid obtained by rotating the region bounded by y = 3 x , x = 2 , x = 3 , y = 0 about the x-axis. 1. V = 3 8 2. V = 3 2 π correct 3. V = 3 4 π 4. V = 3 2 5. V = 3 4 6. V = 3 8 π Explanation: The volume of the solid of revolution ob- tained by rotating the graph of y = f ( x ) on [ a, b ] about the x-axis is given by volume = π integraldisplay b a f ( x ) 2 dx . When f ( x ) = 3 x , a = 2 , b = 3 , therefore, V = π integraldisplay 3 2 9 x 2 dx . Consequently, V = π bracketleftbigg- 9 x bracketrightbigg 3 2 = 3 2 π . 002 10.0 points Find the volume, V , of the solid obtained by rotating the bounded region in the first quadrant enclosed by the graphs of y = x 3 2 , x = y 4 about the x-axis. 1. V = 5 12 cu. units 2. V = 7 15 π cu. units 3. V = 1 2 π cu. units 4. V = 5 12 π cu. units correct 5. V = 1 2 cu. units 6. V = 7 15 cu. units Explanation: Since the graphs of y = x 3 2 , x = y 4 intersect at (0 , 0) and at (1 , 1) the bounded region in the first quadrant enclosed by their...
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## This note was uploaded on 09/20/2011 for the course CALCULUS 7234832 taught by Professor Campsisi during the Spring '11 term at University of Texas.

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6.2-solutions - tran(pt4954 – 6.2 – campisi –(54970 1...

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