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Homework2Key - Irwin Basic Engineering Circuit Analysis 9/E...

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Unformatted text preview: Irwin. Basic Engineering Circuit Analysis. 9/E 1 2.31 Find ‘Irffl. in the network in Fig. P13]. air an e a 3n 4n 9v an Figure P231 SOLUTION: V000 = ’41 KVL'. (moi = #1 +21 +31+e1 \51: 15 1:. \A Va»: ~ACi) V”; “AV ________—_____—__————————-———-_—— Chapter 2: Resistive Circuits Problem 2.31 Inivin, Basic Engineering Circuit Analysis, 9/5 1 2.32 IN; = 3 ‘u‘ in the circuit in Fig P132. find 1’}. I 12 m V5 9 9 m V” = 3 V Figure F232 SOLUTION: Va: V .5. 1= 7-19: = am I T —' EmPs \AVL '. V5 5 *QK‘S V3 ’ 2.\ [YD vsfifiv ____—_—__—_——__—_———_——————————-— Chapter 2: Resistive Circuits Problem 2.32 Irwin. Basic Engineering Circuit Anaiysis, 9/E 1 2.38 Find the power absorbed by the dependent source in the circuit in Fig. P238. 6M! 10 RD Figure P238 SOLUTION: KvL '. 20 = (a Kim-AVG,“ + (90+ \OKIW + mum + \ovxiq,’ 32KT1: ‘ I.” = \.25W\A ’P: Y: 3200 (4.2.5 :03 C~L25m> "P: amsmw ______—____—__—__—.__———_———-——-—— Chapter 2: Resistive Circuits Problem 2.38 Irwin, Basic Engineering Circuit Anaiysis, 9/E 1 2.1;: Find the puwer supplied by each wince in the circuit in Fig. P24]. Figure P241 SOLUTION: R =ik| kll K 2“ %(I2)5 (Ray : 543%12451- Vi 5 V‘: \,i%V ’PmA = Am (ms) Ham 3 LL72 m N 12m = —2m)<i.i%> _____—__—__—____—_——-——-————-—————— Chapter 2: Resistive Circuits Problem 2.41 Irwin, Basic Engineering Circuit Analysis, 9/E 24:; Find IL. in 111:: network in Fig. P244. fikfl Figure P245. SOLUTION: 5 i~< i5 V, -"~‘ QD \vy’; '2 4 3/ Chapter 2: Resistive Circuits Problem 2.44 2 Irwin, Basic Engineering Circuit Analysis. 9/E Problem 2.44 Chapter 2: Resistive Circuits Irwin, Basic Engineering Circuit Analysis. 9/E 1 2.50 Find RAB in the circuit in Fig. P250. 1k!) Figure P2.5o SOLUTION: p... ’R.= (ZKH- union 2k 21.0. ' z - .0- _> Rei-Ahkfl 'R' “‘4‘ VA» 7.111 .._..——!wi RM, : 2m Manama (Rm.- 5% K1?— Chapter 2: Resistive Circuits Problem 2.50 ...
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