Homework4Key

Homework4Key - Irwin. Basic Engineering Circuit Analysis....

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Irwin. Basic Engineering Circuit Analysis. 9/E 1 3.11 Find V0 in the network in Fig. P3.ll using nodal analysis. Figure P341 SOLUTION: V0 : V, —- 6 V0 3 O V Chapter 3: Nodal and Loop Analysis Techniques Problem 3.11 Irwin, Basic Engineering Circuit Analysis, 9/E 3.35 Find In. in the circuit in Fig. P335 using nodal analysis. 12 kl! Figure P335 SOLUTION: CD 1 12 ks! KLL M j I, : 41% + Io 1% : __\CL IZK I, :— AI 'f' 1‘5 lLK VI’VQ— , __\_/L —l— V2 l2_K ’ 3K /9_K 2V!" V2. 3 I414 3V, + 2V2 :- O Chapter 3: Nodal and Loop Analysis Techniques Problem 3.35 2 Inn/in, Basic Engineering Circuit Analysis, 9/E Problem 3.35 Chapter 3: Nodal and Loop Analysis Techniques Irwin, Basic Engineering Circuit Analysis. 9/E 1 3.36 Find 1’; in the circuit in Fig. P136 using nuda] aimhr'gis. 12".Ir 1 m e + 1:}? , T 2 m 1 in L0 Figure P336 SOLUTION: W,» ~— \ \ Chapter 3: Nodal and Loop Analysis Techniques Problem 3.36 2 Irwin, Basic Engineering Circuit Analysis, 9/E Problem 3.36 Chapter 3: Nodal and Loop Analysis Techniques lnNin. Basic Engineering Circuit Analysis, 9/E 1 351 Find It. in the circuit in Fig. P35 l. 5"! Figure P351 SOLUTION: ,, /~~ » N Chapter 3: Nodal and Loop Analysis Techniques Problem 3.51 Irwin, Basic Engineering Circuit Analysis, 9/E 1 3+9:- Using 1001:: analysis. find if; 1'11 111:: circuit in Fig. P190. Figure P3490 SOLUTION: KCL ‘- 1.: I+I2 I: 1"12. KCL‘. '15; I‘TI. I’: I34:I KVL‘. 2k1,+ ik l+2k(-I')= o 2klniéifj2,:35(I-’VI‘>=O “351' - .455 :r?‘:f§75) KVL: 2LI': 12+ 2V1, 2%} Q 1%" 2— w 1L) [2311‘— Zklikipiklj) : :2. \KVL: 2H. + in): meagre} Chapter 3: Nodal and Loop Analysis Techniques Problem 3.90 2 Irwin, Basic Engineering Circuit Analysis, 91E “L " “‘5 *%rt:-:.3+ Skip ikIL’2kI3+OIL,=0 v2k 1\«2k11—r2k13+ 01,:12 2k1‘+ LkIl+ 013+ ikTV:ll :01!“ I” 013* I912“ ——_—_———_—_——————-———— Problem 3.90 Chapter 3: Nodal and Loop Analysis Techniques Irwin, Basic Engineering Circuit Analysis, 9/E 1 3.94 Usng 1041}: analysis. find 1’}. in the network in Fig. Plflri. 1kfl + 2 Kfl in Figure P3435. SOLUTION: 1 m + 2m U0 Chapter 3: Nodal and Loop Analysis Techniques Problem 3.94 2 Irwin. Basic Engineering Circuit Analysis. 9/E KVL '. ik1+ ikI': 2V0 v0: 2m, 1k(IyI.)+ 1“ (I343 )= 2(2k 1.1) ‘_ ikl‘ +2k15 _ SkIEiz o? KVL'. 2V0 = 1kI|+ ikIla- 2kIH \lo: 1k 11+ 1k122kL1= on I\‘11.‘. 3’ 4m ' 01H 01,: ik13+3>k11;i7_ -ik1|+ 01,4 Zing—511.1?!) 1L1” 11:1fl 0:5 -2L1\1;o Jn 4N,- mod'Mx MW (4% combo AL/DTMQMQDL/ ’ a" “idem, cu '. Gib/3 ~43) (Meow-ac, W yam—«a Mo mozwcmy, : VD; Act 0Uth {9pm CLO/youif) Problem 3.94 Chapter 3: Nodal and Loop Analysis Techniques ...
View Full Document

Ask a homework question - tutors are online