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Homework7Key - Irwin Basic Engineering Circuit Analysis 9/E 5.55 In the[mm-mi in Fig Phjh find 1 wing Thc'wnin‘s theorem Figural P555 SOLUTION

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis. 9/E 5.55 In the [mm-mi; in Fig. Phjh. find 1; wing Thc'wnin‘s; theorem. Figural P555 SOLUTION: 3kI = O'SVOC. I: 0‘16'7'm\/oc, Vac: 2k(o-I6?m%e,)+12 4%: 18V I“; .15.“: iBmA iknzk Chapter 5: Additionai Analysis Techniques Problem 5.55 2 lein, Basic Engineering Circuit Analysis, 9/E KT": Vac. = 18 ziksz Problem 5.55 Chapter 5: Additional Analysis Techniques Irwin, Basic Engineering Circuit Analysis, 9/E 5.61 Find l“; in me circuit in Fig. Pit-l using Thriwrriir‘e; [IZICL'JFL‘J'JI Figure P5611 SOLUTION: Chapter 5: Additional Analysis Techniques ' Problem 5.61 2 INVin. Basic Engineering Circuit Analysis, 9/E V1: V1 x4: 6V v3: 12v V2: 2 5v \LVz _ V; J M if“ ‘9“ : — 0-1875 m9 VHC 2k. D(_1)=_o-316V Problem 5.61 Chapter 5: Additional Analysis Techniques Irwin, Basic Engineering Circuit Analysis, 9/E 1 5495 Find RL iii the network in Fig. P396 in wider in achieve maximum puwer transit'ei'. Figure F536 SOLUTION: ____-_—______—___—___—________————— Chapter 5: Additional Analysis Techniques Problem 5.96 Irwin. Basic Engineering Circuit Analysis, 9/E 1 593 Find R1: i'ur maximum pnwcr iraumi'cj' uml the Humimum rim-w than can he li'zmat'crml in mi: [maid in Fig. P598. 2 mA Figun: F538 SOLUTION: Chapter 5: Additional Analysis Techniques Problem 5.98 i 2 Inivin, Basic Engineering Circuit Analysis, 9/E VAC: 4v ékfl. 6V Voc V" , 6t _. V DC <3k+ek><6)'4 Vocs 8‘! F0)» maxfmwnlmww tmsjlu.) EL: KT”: ‘ “’6 R: limx im X44“ 4"“ Fw=\*\ Problem 5.98 Chapter 5: Additional Analysis Techniques Inn/in, Basic Engineering Circuit Analysis. 9/E 1 .102 Charisse R in the network ul' Fig. PSJEIE for maximum L a power transit'ci'. 5H1 Ekfl Figure P5402 SOLUTION: 5 k1! 5 m e 12v 100! 0 \/0(, LC: 101(1.2m) =121.2mn RT”: _ = [2l‘2m Chapter 5: Additional Analysis Techniques Problem 5.102 2 Inn/in, Basic Engineering Circuit Analysis, 9/E 11%;. maximum Patna» ,biaqu, KL: km: 79.0.. Problem 5.102 Chapter 5: Additional Analysis Techniques lrwin, Basic Engineering Circuit Analysis, 91E 1 5.103 Fiml RL i'ur maximum [Him-w transfer and the maximum power that can he transferred in the Jihad in Fig. Pililfi. 1 mA Figure P5403 SOLUTION: 5 Chapter 5: Additional Analysis Techniques Problem 5.103 2 Irwin, Basic Engineering Circuit Analysis, 9/E KCL or \lx‘. 1m: \/><_ V1- V0 1k fir 2i. 3VI‘V0= 2 KCLax V0: Vx-Vo : 4V3 +_\[b_ 2L 1000 3k Z! V“, -i- 5V0 = 0 V1. 0‘218V V0... -1.ie7v Ln = _\_/o_ : —I-l6'r’ , -0-38‘ImA 3 3k. 3 "il4 = B'Gk—D— ——O-38‘1m pm. maxfmum Fwy}. Xi’an/lift.) EL: 2TH: , Problem 5.103 Chapter 5'. Additional Ana|ysis Techniques Irwin, Basic Engineering Circuit Analysis, 9/E 3 IL -_:. ’1'4" 3-GL+ 3.6k = —- 0'194-mA P = If KL ... (- 0494973519: O'l36mN _____—____—_______—__—_.__——————-——————— Chapter 5: Additional Analysis Techniques Problem 5.103 ...
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This note was uploaded on 09/21/2011 for the course EE 2300 taught by Professor Staff during the Spring '08 term at Texas State.

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