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Homework7Key - Irwin Basic Engineering Circuit Analysis 9/E...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis. 9/E 1fi+2 Find this Lupin impedance 1(5) all the new-wk in Fig. P143. I an 111β€”.Β» 1331a 5 m 2H 15’ β€œ111 2;: Β«hr Figure P142 SOLUTION: Z(S)β€”- 1n , 25 2(5) =[o>wβ€˜2s>IIi]r?β€” H il3 Hi 2(3): [(arzsgw +2JH1'g/Ii i+2+2Β§ Z(s): [i123 +L]//1/3H1 s 2(5) =[a?+Β§512(3+252],’ 1’5 [/1 Β«5+2: 2:3); gr: 1/ H: = 6 2a) 39 1: 25-9 (ifs) em "1 6+2; T'IS Chapter 14: Application of the Laplace Transform To Circuit Analysis Problem 14.2 2 lrwin, Basic Engineering Circuit Analysis, 9/E 2(5) : 8"?”GS 331- 02’3" W i 35 1’ 6323-314: (31'24)(4) 2(3) = 8"” 63 M l i 631+l0uβ€”3 I 8+6; L 5JL+IOΒ£+3 2(3) = 8+53 63"+/0.(’+3 8+6”: 6:5-l03r3 ssh/0M3 2(4) 2 6&1’8 61Β°3- /6u-ll Problem 14.2 Chapter 14: Application of the Laplace Transform To Circuit Analysis Irwin, Basic Engineering Circuit Analysis. 9/E 1 11...} Use Laplace transforms and nodal analysis in [111:] Mr] fair I El in the network shown iii Fig. PM}. Assume zci'ii initial Ciimlitiiina. Figure Fig.3 SOLUTION: KQL we 1.: 1,3): Il(s)+I3 (S) lg β€”v,(s) z v.8) V,(s)+ s/g ’L \9 T fir/5 _/_2_ . V,(s) β€œ : Viβ€œ) SV,($)+€ 2. J T 9. s % 44(3)], Β£V,(s)+ 51v,($}+€s left" 6V, (3) z o?i/,(5) +ng'\/,(s) +63 VIβ€œ)[5L+11-2.]; IQβ€”es Viβ€œ) 2 231β€”65 : 6(a-s) Salβ€”ST?β€” $23-$12. Chapter 14: Application of the Laplace Transform To Circuit Analysis Problem 14.3 " l 2 Irwin, Basic Engineering Circuit Analysis, 9/E Iris): Lag)... 5 555+?" 2. 2(3); lllSLβ€˜rfi'W)’ 690*) WWW...β€œ SUEHWH WW 9.. LR); llgjflvfllgf 9β€˜] "rΓ©LLβ€”Β«Ils 0'2 5 ( $13M 1- x) W Problem 14.3 Chapter 14: Application of the Laplace Transform To Circuit Analysis Irwin, Basic Engineering Circuit Analysis, 9/E 3 A: M $(s+Ji +J’ 5: ~I/,.+jj:_Β£ A a 5.24 Law" 2.Β» in): [6+ 6le (WWW! (Eefggdflukm Chapter 14: Application of the Laplace Transform To Circuit Analysis Problem 143 Irwin, Basic Engineering Circuit Analysis. 9/E 1 1:..4 Find volt). r Cl. in the [win-mi; in Fig. P144 1151' mg nmlc minutinm. {’_rii{r} v Figure P144 SOLUTION: SW56) f 5V0 (3}? V0 (5) 'l : O 0?, (3β€”H) (8+1) 8V0 (S) [($+l)(_1+3β€”)] 1, 3V0 (β€œg/OS), I ___ 0 ~ W o2 3V0 (4) (5+1) (0a)] + 2910(1) r 2V0 (9β€”2: 0 V0 (3) $(x +/)(i 1;)1-23 +2.] = 2β€” Voa) : Legβ€”β€œM (w) (5’;β€” 2s)Β’2: r2, Chapter 14: Application of the Laplace Transform To Circuit Analysis Problem 14.4 2 . ' Irwin, Basic Engineering Circuit Analysis, 9/E Veg) .- 2β€” Mβ€” (xw) ($24Β» 24 +3.) V0 (S); A, + A). _r A;* SH \frl-j'l 6+ Irf/ A2; 2 (MHz) rig-1 a; i V08): 4 - I , I 5+) gar/7β€˜: β€˜51.,sz Problem 14.4 Chapter 14: Application of the Laplace Transform To Circuit Analysis Irwin, Basic Engineering Circuit Analysis, 9/E 1:..5 Liar: Laplace tramt'm'am in find tilt} 1151' r [l in 111:: HCIWUFR alum-'1] in Fig. PILLS. Amurnc Kent- initial wudilimm. Figure Fig.5 SOLUTION: KCLI L6) = 1(5) *r 116) I($): Iβ€˜ (S) ' 11(3) KVL chfvt' 1,0979: 143(5))? 1,313); 5’5 MW ilS [1. (9β€” am]: 5/; (1+ %)I,($) .. 1/3 ILG) = 5]: KVL mManht Β«6007;: Β£101 (3)1β€œ ii 61(3)) 53:9 4102 (9- 3iβ€” [1,(3)-β€”11($3] 2:199 _. ifs Irβ€œ) 1' (ah- l/S) 1713): Β£12. Chapter 14: Application of the Laplace Transform To Circuit Analysis Problem 14.5 2 lrwin, Basic Engineering Circuit Analysis, 9/E β€”~β€”β€”-β€”-β€”β€”β€”_β€”_β€”._β€”___β€”β€”β€”β€”_ Problem 14.5 Chapter 14: Application of the Laplace Transform To Circuit Analysis Irwin, Basic Engineering Circuit Analysis. 9/E 1 n+6 Fm' the notwan ahnwn in Fig. P145. fiml {air}. I 0. 1n 1": Figure Fig.6 SOLUTION: m 0x1: ms) = 11(3) + Iva) 4- β€”v.<s) 3β€” : VHS) +317 + \/,(s) S i 2 iβ€”\/,(s)- SV,(S)+ o” +6V,($) S Jr] :2. 5+! * L3C$)+%]: g β€˜ O21 4' 1H \4(3)[3(5)+2]: 3” 8"?β€œ 6(sβ€”rl) mg) : β€œMLβ€”rang W !(:-n) (33Β») Chapter 14: Application of the Laplace Transform To Circuit Analysis Problem 14.6 2 Irwin. Basic Engineering Circuit Analysis, 9/E Io (3) : β€˜4β€œ) 03 1w): _1_[2s_f:r_8_s_1.8 7" J(&+/)(&s +1.) %(9)= #5631} 4-3 r4) 30w) (:1- z/a) β€˜9β€˜β€ J-r 1’3 1/3 (Β«x 2β€˜-r 4: +4) > A (1+ I)(\Β§+’*/3) + 6(3)@+>/5)+ C(syxw) 4463: 0 WWW 3(4) 4:2. Knth β€”i 3406'?β€” 4++) : BMW :45) -1/3: 5:-1 M \r: -β€” ac Maw +<β€”>/a)+ +)= C(β€˜WC’fi 1Β» Problem 14.6 Chapter 14: Application of the Laplace Transform To Circuit Analysis Irwin, Basic Engineering Circuit Analysis, 9/E ______________________β€”β€”β€”β€”β€”β€”β€”β€”β€” 45H? β€˜ 39 +4l= C(*"β€˜/3)(i/s) _________________________._β€”β€”β€”β€”β€”-β€”β€”β€”β€”β€”β€”β€”β€”β€”β€” Chapter 14: Application of the Laplace Transform To Circuit Analysis Problem 14.6 Irwin. Basic Engineering Circuit Analysis, 9/E 1:}; Fur the nclwnrk sham-n in Fig. P143. find walk). I Cl. using nmlc min-cinema. Figure Fm: sownomw) 1 \ 1 2’5 Chapter 14: Application of the Laplace Transform To Circuit Analysis Problem 14.7 Irwin, Basic Engineering Circuit Analysis, 9/E v.0) ; oil-r & W 53:;- 2: H. Β«3114. mm) = (Β§s++)(Β°?uzβ€”) 3(Szrr21-rL) W8): +(Ifz) (f-tl) 6(5’3- 21+ 2.) 1;β€œ); \l,(;) «’24- 3/3 131;) .- 3V, (1β€˜) on”. vow z 103(3)) V08); .9 fibulaβ€œ) o?($-n) J(r’=ra?:+2. VOA); gem-r24 323’ 41+; V0 (3): ag-cf’) (Β«I uf1)(Β£+/+i1) Problem 14.7 Chapter 14: Application of the Laplace Transform To Circuit Analysis Irwin. Basic Engineering Circuit Analysis, 9/E A: oz I1- 9I.) ____________________.___β€”β€”β€”β€”β€”-β€”β€”β€”β€”β€”β€”β€”- Chapter 14: Appiication of the Laplace Transform To Circuit Analysis Problem 14.7 ...
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