ejercicios de thevenin.docx - INTEGRNATES FABRICIO TIPAN Y JHOSTIN OYOS DOCENTE ING Oscar Lara CARRERA Electromec\u00e1nica NRC 4323 CURSO Primero B

ejercicios de thevenin.docx - INTEGRNATES FABRICIO TIPAN Y...

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INTEGRNATES: FABRICIO TIPAN Y JHOSTIN OYOS DOCENTE: ING. Oscar Lara CARRERA: Electromecánica NRC: 4323 CURSO: Primero B 1.-Calcule la resistencia de Thevenin RTH las terminales a y b haciendo cero todas las fuentes del circuito R 12 = R 1 R 2 R 1 + R 2 = 4 6 4 + 6 = 2.4 Ω R 34 = 6 3 6 + 3 = 2 Ω Rth = 2 Ω + 2.4 Ω = 4.4 Ω VR 2 = VAB = V 1 R 1 R 1 + R 2 VR 2 = 6 6 4 + 6 = 3.6 v CIRCUITO EQUIVALENTE DE THEVENIN RT = 4.4 Ω + 4 Ω = 8.4 Ω I = 3. 6 v 8.4 Ω = 0.428 A VRL = 0.428 A 4 Ω = 1.71 v 2.-Calcule el equivalente de Thevenin del siguiente circuito. Rth = ( 5 5 ) 5 + 5 + 6 3 6 + 3 = 4.5 Ω Va = Ia R = ¿ 12 5 + 5 = 6 v Vb = Ib R = ¿ 12 6 + 3 = 4 v CIRCUITO EQUIVALENTE DE THEVENIN
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RL = 5 Ω RT = 4,5 + 5 = 9,5 Ω I = 2 9,5 = 0,21 A VRL = 0,21 5 = 1,05 v 3.-Encontrar el circuito equivalente de Thevenin a la izquierda de los terminales a y b. con el resultado obtenido calcule la corriente I que pasa por la resistencia de 9Ω. R 1 = 30 6 30 + 6 = 5 Ω R 2 = 5 + 5 = 10 Ω Rth = 10 10 10 + 10 = 5 Ω LEY DE VOLTAJE DE KIRCHOOF V 1 + V 2 + V 3 = 0 24 ( 30 I 1 ) ( 6 I 1 ) + ( 30 I 2 ) = 0 24 = 36 I 1 30 I 2 (1) ( 10 I 2 ) ( 5 I 2 ) ( 30 I 2 ) + ( 30 I 1 ) = 0 45 I 2 + 30 I 1 = 0 (2) I 1 = 45 30 I 2 = 1,5 I 2 REENPLAZANDO E (1) 36 ( 1,5 I 2 ) 30 I 2 = 24 = ¿ 54 I 2 30 I
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  • Fall '09
  • WARFIELD
  • Teorema de Thévenin, Oscar Lara, Rth=, circuito equivalente de Thevenin

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