LES_I_M06_01 - Professur fr Leistungselektronik und...

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Professur für Leistungselektronik und Messtechnik Prof. Dr. J.W. Kolar Leistungselektronische Systeme I Übung Nr. 6 Musterlösung Übung 6 1) Eingangsspannung U 1 540V := Induktor Induktivität L 0.57 μ H := Schwingkreiskapazität C 100nF := Trafo Übersetzungsverhältnis n1 0 := Schaltfrequenz f s 100kHz := T s 1 f s := T s 10 μ s = T + T - D + D - U 1 u C DC C u C i L L Idealer Trafo: 10:1 Induktor i DC U cmax 540V := U cavg U 1 2 := L p Ln 2 := I Lavg 0 := ω 0 1 CL p := Z 0 L p C := 0...0.25T s : I L0_0 0A := U C0_0 0V := U d_0 540V := u C_0 t () U 1 U 1 cos ω 0 t := i L_0 t U 1 Z 0 sin ω 0 t := 0.25T s ...0.75T s : I L0_1 i L_0 0.25T s := U C0_1 u C_0 0.25T s := U d_1 := u C_2 t U C0_1 cos ω 0 t 0.25T s Z 0 I L0_1 sin ω 0 t 0.25T s + := Trigonometrische Umformungen 1) oder Analogie-Überlegungen: => u C_2 t U 1 cos ω 0 t 0.5T s := i L_2 t U 1 Z 0 sin ω 0 t 0.5T s := 0.75T s ...T s : Analoge Formel wie für 0. ..0.25T s
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1) u C_2 t () = U C0_1 cos ω 0 t 0.25 T s () Z 0 I L0_1 sin ω 0 t 0.25 T s + = U C0_1 cos ω 0 t 0.25 T s Z 0 U 1 Z 0 sin ω 0 T s 4 sin ω 0 t 0.25 T s + = U C0_1 cos ω 0 t 0.5 T s 0.25 T s + U 1 sin ω 0 T s 4 sin ω 0 t 0.5 T s 0.25 T s + + = U C0_1 cos ω 0 t T s 2 cos ω 0 T s 4 sin ω 0 t T s 2 sin ω 0 T s 4 + U 1 sin ω 0 T s 4 cos ω 0 t T s 2
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LES_I_M06_01 - Professur fr Leistungselektronik und...

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