Quiz 5 SolutionsQuestionA 10 F capacitor is charged with a battery of 10V. After charging, this capacitor is discon-nected from the battery and connected to another capacitor of 5 F.a. Find the initial charge on the 10 F capacitor and the potential energy stored in it.b. Find the final potential difference across the capacitors, and the charges on each ofthe capacitors.c. Find the final potential energy stored in the two capacitors.d. How much is the total final potential energy? Is it same or different than the initialpotential energy?e. (Bonus question, no penalty if wrong) Depending on what you find, explain why isthe total final potential energy same/different than the initial potential energy?Solutiona) Voltage across the 10μFis 10V. Therefore the charge on itQintial=CV= 10×10 =100μC, and energy isU=CV2/2 = 5×10(-4)J. Let the charge on this beQinitial.b) After charging the 10μF(call it capacitor 1) is connected to uncharged 5μF(capacitor2). Charge will thus flow from the charged capacitor to the uncharged. In this flow of chargethough, the total initial charge will be conserved. Thus,Qinitial=Q1,final+Q2,final(1)The charges flow because there is an electric force pushing them. This electric field iscoming from the difference in potentials of the two capacitors. Capacitor 1 starts from 10V,and capacitor 2 starts from 0V. As charge is transferred from capacitor 1,Q1decreasesandQ2increases, and becauseV=
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