Eq%20Ch.%203(1) - =(3.29 2g θ sin v h 2 2 =(3.30 R h

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0 0 0 0 2 0 0 , , , 1 2 x x x y y y v v x x v t v v gt y y v t gt = = + = - = + - (3.16) (3.17) (3.18) (3.19) 0 0 2 0 0 0 0 0 0 ( cos ) 1 ( sin ) 2 cos sin x y x v t y v t gt v v v v gt θ = = - = = - ( 3.20) (3.21) (3.22) (3.23) 2 0 2 2 0 0 (tan ) 2 cos g y x x v = - (3.28) For x 0 = y 0 = 0: 2 0 0 sin 2 v R g = (3.32) g sinθ v t 0 0 highest
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Unformatted text preview: = (3.29) 2g θ sin v h 2 2 = (3.30) R h...
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This note was uploaded on 09/21/2011 for the course PHY 1500 taught by Professor Staff during the Spring '09 term at University of Central Florida.

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