Recit%20Ch%201(1)

# Recit%20Ch%201(1) - PHY2053 RECITATIONS SPRING 2011...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: PHY2053 RECITATIONS, SPRING 2011 Recitation 1 (Chapter 1) Jan 17-21 Ch. 1 # 15. The corners of a square lie on a circle of diameter D = 0.35 m. The side of the square has a length L . Find L . REASONING: Using the Pythagorean theorem (Equation 1.7), we find that the relation between the length D of the diagonal of the square (which is also the diameter of the circle) and the length L of one side of the square is 2 2 2 D L L L = + = . SOLUTION: Using the above relation, we have 0.35 m 2 or 0.25 m 2 2 D D L L = = = = Ch. 1 # 21. Three deer, A , B , and C , are grazing in a field. Deer B is located 62 m from dear A at an angle of 51° north of west. Deer C is located 77° north of east relative to dear A . The distance between deer B and C is 95 m. What is the distance between deer A and C ? ( Hint : Consider the law of cosines given in Appendix E .) REASONING: The drawing shows the location of each deer A, B, and C. b = 62 m c = 95 m γ = 180 ° - 51 ° - 77 ° = 52 ° γ α β A B C 77° 51° b a c Applying the law of cosines (given in Appendix E) to the geometry in the figure, we have a 2- 2 ab cos γ + (b 2- c 2 ) = which is an expression that is quadratic in a. It can be simplified to...
View Full Document

## This note was uploaded on 09/21/2011 for the course PHY 1500 taught by Professor Staff during the Spring '09 term at University of Central Florida.

### Page1 / 3

Recit%20Ch%201(1) - PHY2053 RECITATIONS SPRING 2011...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online