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Unformatted text preview: v y is zero, so y p 1/ 2 2 p 1/ 2 v v g t v 5.0m / s g 2.5m / s t 2.0s = == = =The weight on the planet is: ( 29 ( 29 2 p m w mg 32kg 2.5 80N s = = = The weight in lb is: ( 29 1lb w 80N 18lb 4.448N = = 1) A 2180 kg car is traveling with a speed of 12.0 m/s along a horizontal straight line. What is the magnitude of the horizontal net force that is required to bring the car to a halt in a distance of 40.0 m? We can find the force from: F ma = We need to determine the acceleration, a, and then F: ( 29 ( 29 2 2 f 2 2 2 v v 2ax v a 2x 2180kg 12m / s mv F 3924N 2x 2 40m = = += = = = ...
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This note was uploaded on 09/21/2011 for the course PHY 2053 taught by Professor Vellaris during the Spring '08 term at University of Central Florida.
 Spring '08
 Vellaris
 Physics, Mass

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