This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Math 2144, Exam I, Sept. 20, 2010 Name: Score: Please read the instructions on each problem carefully, and indicate answers as directed. Show details in your work. If you simply give a solution without steps of how you derive this solution, you may not get credit for it. The total is 50 points 1. (5 points) A box with an open top has volume 2 m 3 . The box has a square base and the length of a side of the base is a . Express the surface area of the box S as a function of a . Solution The area of the base, which is a square, is a 2 . Assume the height of the box is h , the the total volume is V = a 2 h . We have a 2 h = 2 h = 2 a 2 The box has a bottom and four sides (no top lid). Therefore the surface area is A = (area of the bottom) + (area of four sides) = a 2 + 4 ah Since h = 2 a 2 , we have S = a 2 + 4 a 2 a 2 = a 2 + 8 a 1 2. (6 points) Find the domain of the function f ( x ) = log 4 x 2 + log 4 ( x + 5) log 4 8 x Then express the function in a single logarithm....
View Full
Document
 Fall '08
 PAGANO
 Math, Calculus

Click to edit the document details