quiz1-sol - Quiz 1 Math 2153, Calculus II Aug. 26, 2011 1....

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Quiz 1 – Math 2153, Calculus II – Aug. 26, 2011 1. Evaluate the integral Z π 0 t sin 3 t dt Solution This integral can be computed using integration by parts. Set f ( t ) = t and g 0 ( t ) = sin 3 t . The we have f 0 ( t ) = 1, g ( t ) = - 1 3 cos 3 t and Z t sin 3 t dt = t ± - 1 3 cos 3 t ² - Z 1 × ± - 1 3 cos 3 t ² dt = - t 3 cos 3 t + 1 3 Z cos 3
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This note was uploaded on 09/22/2011 for the course MATH 2153 taught by Professor Staff during the Fall '08 term at Oklahoma State.

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