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Unformatted text preview: x back. Notice that sec = x/ 7, we have tan = sec 2 1 = p x 2 / 71 . Hence the integral is Z x x 27 dx = 7 tan + C = 7 p x 2 / 71 + C = x 27 + C Solution 2 Use substitution. Set u = x 27, then du = 2 x dx The integral becomes Z x x 27 dx = 1 2 u du = u + C = x 27 + C...
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This note was uploaded on 09/22/2011 for the course MATH 2153 taught by Professor Staff during the Fall '08 term at Oklahoma State.
 Fall '08
 staff
 Calculus

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