Unformatted text preview: u du =2 √ u + C =2 √ 3x + C Therefore, lim t → 3 Z t 2 1 √ 3x dx = lim t → 3 (2 √ 3x )± ± t 2 = lim t → 3 (2 √ 3t + 2 √ 32 ) = 0 + 2 = 2...
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This note was uploaded on 09/22/2011 for the course MATH 2153 taught by Professor Staff during the Fall '08 term at Oklahoma State.
 Fall '08
 staff
 Calculus

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