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ese271fall04second

# ese271fall04second - Prob 1(25 points(a Find the phasor for...

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Unformatted text preview: Prob. 1. (25 points): (a) Find the phasor for 3 sin(3£ + 30°) -- 4cos(3t + 155°) as a, single complex number in rectangular form. (b) Find the cosinusoid for the phasor (4 - 3'4)(*3 - i4) ‘2 + 3'4 (Assume w = 2.) (a) 3 cu.(3'f+30°—90°) —- 4 and-(3t +N‘T“) [> 3440’ — I’LL—~15?" :- 3 an {-60') +J‘BAH‘» (*440‘) - QLGa-a (Ar-J") —J'4'- MOIJ“) -.— Ar -J' arw ”awn—,1 (#23) = SUML ~j4.2?o (6) (4” 47‘4") (5- g'ld’ﬁr 4-4/0) W (”6.6" = 6.31: 4—way : {_ 31! iii“ 1 6.32 mat +?x..r°) 3: 5331 m0? -—2<ﬁP.5-"‘) Prob. 2. (25 points): ‘ Find the effective value (that is, the RMS value) of the voltage ﬁt) on the 4 ﬂ resistor. + 42'“)— 411 (.93 2t if J. 8F 2 (AC/ 1/9110.er 59'1”?) (D? lc\urrenf source) 0:2 Supeypas [169» AC wife}? Sconce alone: 4. 2 2 4 _ ____._2_.—- : o z I; 4J—o V: 2 4—44 ‘ 1-] Eur L H _ ErrECjtl’E Vilne of nrlt) -— fi- -j 06' carren'é Insure: 4/9143: 4 } I 03%- IU" :' 2 vnhl: DC It ‘ Eﬂfﬁota'Vd Vﬂl'u? of 17“ Va 67! —; 2 will: Prob. 3. (25 points): Using the virtual-short virtual-open model of the op amp, ﬁnd no (t) as a msinusoid. ALFO} ‘J-z _ 2 v, - 4 252-12 _ SB, K:(,_Ja)2-:2J?Li‘_° Prob. 4. (25 points): Find the current 1'20) as a. cosinusoid by means of a. mesh analysis using the mesh currents shown. ...
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