susb014 - 1 ·1'-~o.OO rnL / a.O mmotes mol -' >(=...

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2. Sketch the titration curve for titrating 0.1461 g. of dl-mandelic acid with 0.05 M. sodium hydroxide solution. Use data from Table 1. Mark and label the end point and the half titration point. 0.14(0\ q. ::: \4G.\ mg· ~ROt'Yl TA BLf 1.. : d.1- MandelLc Acrd (!-ICg H1 03/ MolQr Mass: fSa.1 ~/mol l~ 1~.1 m~ X 16~.' (molarma~s) \0 X mmol \ \'il. (x m01ol) ::; 14~.I_mj 1.1 '5~.1 ;(::. 9 G05Sa rt\rYlO 1 OH - <t--" • 9Q,Otj5a . .J • mmol aCLu ( 1. ml.)(O.Oc; rnmo1!mL) -=- .~G055~ MY\101 of-OH- ~ i== Iq.a ml (Etvivalence P?IYltJ • POint") 17.<; 0.0 IQ.a mL /2:::.Cj.(QOmL(Half--Trt"Yl1"hOt'l 00 2.5 5.0 • 1.012.5'5.0 ( 3. An unknown acid (0.2922 g) was titrated with 0.100 M. sodium hydroxide. The equivalence ~ ~ point required 20.00 mL. The pH at the point where 10.00 mL had been added was 4.40. added) Identify the unknown acid, using data from Table 1. Molarity::::. :tF of moles X-.:ftof moles = «Q.O mmoLes liters O./ooM=v: X o.aq~aq -P aqa.a m9 '-., ~qQ.a m9. .:.,=: I~.l ~/
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Unformatted text preview: 1 ·1'-~o.OO rnL / a.O mmotes mol -' >(= (O.JOOM)(ao.ooml.) Aceordlrig -to Table::L, -the unl(nown (lel/:! 4. X mg of an unknown acid was titrated with 0.110 M sodium hydroxide. Calculate X by is tAC«Olc Acid} subtracting the last two digits of you student ID in mg from 400 mg. The equivalence point is a~ 25.00 mL. What is the molar mass of the unknown acid? Heela A~ili (II)*'O~15lO'1g5} Name CHE I';4-4E Section 1. Adipic acid has a pK a of 4.40. What is its K a ? Ka ~ 10-r\<o.-== 10 -4· to :=:: ~-3--=. 9;;;"-9-X-W---S-::;:-I<--'o.\ ID~ I0'1ISC,1SS l~ two diqits of Siu.dent ,() t4olo.rr~ == #&r moles 400ma:-BS mq;= 315 mg. .~ uters) J ••• (volu.rne (as.Ooml) (O.IIOM)= ~.'1S rnmoles 3i 5mq.-::: 114. S 9/ mol ~. '15 mmoLes is -the molar mass • o~ the u.nknoW n aCLd...
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This note was uploaded on 09/21/2011 for the course CHE 131 taught by Professor Kerber during the Fall '08 term at SUNY Stony Brook.

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