helpfileforQ3onassignment3

helpfileforQ3onassignment3 - p 0.93 we have C 8 , 8 .93 8 1...

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Example: An airport limo service has experienced that the probability that a passenger with conform booking will actually use the service is 0.93 An van of the service can carry 8 passengers. The van is fully booked. If the passenger decisions are independent, then use the binomial distribution a) Find the probability that all 8 of them will show up. b) Find the probability that at least one of them will not show up. a) If we are going by formula approach Probability of x successes out of n C n , x  p x 1 p n x where C n , x n ! x ! n x ! For 8 out of 8 successes, with
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Unformatted text preview: p 0.93 we have C 8 , 8 .93 8 1 − .93 8 − 8 .93 8 (you could obtain this step even without using the binomial formula, but I just 1 want to keep the settings) . 5595818096650401 If we are using a TI83plus b) at least one of them will not show up is the complement of the event that all of them show up We just computed the probability that all of them will show is 0.5596 2 the probability that at least one of them will not show up is 1 − .5596 0.4404 3...
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This note was uploaded on 09/22/2011 for the course STAT 101 taught by Professor Unknown during the Fall '08 term at Alabama State University.

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helpfileforQ3onassignment3 - p 0.93 we have C 8 , 8 .93 8 1...

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