exam3_solution

exam3_solution - ECE321 Spring 2008 Exam 3 Solution Outline...

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ECE321 Spring 2008 Exam 3 Solution Outline Problem 1 N as 33 6 3 363 3 6 3 36 () T := N slts 12 := P4 := N slts P 3 = W as 1 1 2 + 6 + [] := j2 1 2 .. := k1 1 1 .. := W as j W as j1 N as := W as T 123456789 1 0 1 1 1 2 1 -3 -6 -3 3 6 3 -3 -6 -3 3 6 3 = Problem 2 w as 100 cos 4 φ s = w bs 250 sin 4 φ s = i as 5 cos ω e t π 8 + = B 1.2 cos ω e t π 8 + 4 φ s = μ 0 4 π 10 7 :=
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Expanding B we have B 1.2 cos ω e t π 8 + cos 4 φ s () 1.2 sin ω e t π 8 + sin 4 φ s + = Also B F g μ 0 = F g μ 0 B = Finally Fw as i as w bs i bs + = so 500 cos ω e t π 8 + cos 4 φ s i bs 250 sin 4 φ s + g μ 0 1.2 cos ω e t π 8 + cos 4 φ s 1.2 sin ω e t + + = which is satisfied if g 500 μ 0 1.2 := g 5.236 10 4 × = i bs 2 sin ω e t π 8 + = Problem 3 w as 20 sin 3 φ sm = B cos 3 φ sm 100 t + = r 0.1 := l 0.1 :=
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exam3_solution - ECE321 Spring 2008 Exam 3 Solution Outline...

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