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hw12_solution - ECE321 Spring 2008 Homework 12 3 Ll1:= 1 10...

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ECE321 Spring 2008 Homework 12 L l1 1 10 3 := L l2 0.5 10 3 := L m 100 10 3 := ω e 2 π 60 := r 1 2 := r 2 3 := N 12 10 := Problem 51 Z oc r 1 j ω e L l1 + j ω e L m + := Z oc 38.129 = arg Z oc ( ) 180 π 86.993 = Problem 52 Z sc r 1 j ω e L l1 + 1 1 j ω e L m 1 r 2 j ω e L l2 + + + := Z sc 5.016 = arg Z sc ( ) 180 π 9.158 = Problem 53 Z sc 1 N 12 2 r 2 j ω e L l2 + 1 1 j ω e L m 1 r 2 j ω e L l2 ( ) + + + := Z sc 0.06 = arg Z sc ( ) 180 π 5.85 =
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