{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

hw9_solution

# hw9_solution - EE321 Spring 2008 HW#9 Problem 37 Note I...

This preview shows pages 1–5. Sign up to view the full content.

EE321 Spring 2008 HW#9 Problem 37 Note: I have adjusted array indices to start as 1 in this sheet N as 10 20 20 10 10 20 20 10 10 20 20 10 10 20 20 10 () T := By inspection N sslt 16 := P4 := Now we have W as 1 1 2 1 N sslt P i N as i = := W as 1 30 = Next R 2N sslt .. :=

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
W as R W as R1 N as := W as T 1 2 3 4 5 6 7 8 9 1 01 11 21 31 41 51 6 1 30 20 0 -20 -30 -20 0 20 30 20 0 -20 -30 -20 0 20 = j1N sslt .. :=
51 0 1 5 40 20 0 20 40 W as j j Problem 38 n br φ r () 262 cos 8 φ r 2 π 3 := By inspection P 16 := Recall

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
w br φ r () 1 2 0 2 π P φ r n br φ r d 0 φ r φ r n br φ r d = s'=c Thus c'=-s w br 1 2 0 2 π P φ r 262 cos 8 φ r 2 π 3 d 0 φ rf φ r 262 cos 8 φ r 2 π 3 d = w br 1 2 262 8 sin 8 2 π 16 2 π 3 sin 0 2 π 3 262 8 sin 8 φ rf 2 π 3 0 sin 0 2 π 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 8

hw9_solution - EE321 Spring 2008 HW#9 Problem 37 Note I...

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online