hw9_solution

hw9_solution - EE321 Spring 2008 HW#9 Problem 37 Note: I...

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EE321 Spring 2008 HW#9 Problem 37 Note: I have adjusted array indices to start as 1 in this sheet N as 10 20 20 10 10 20 20 10 10 20 20 10 10 20 20 10 () T := By inspection N sslt 16 := P4 := Now we have W as 1 1 2 1 N sslt P i N as i = := W as 1 30 = Next R 2N sslt .. :=
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W as R W as R1 N as := W as T 1 2 3 4 5 6 7 8 9 1 01 11 21 31 41 51 6 1 30 20 0 -20 -30 -20 0 20 30 20 0 -20 -30 -20 0 20 = j1N sslt .. :=
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51 0 1 5 40 20 0 20 40 W as j j Problem 38 n br φ r () 262 cos 8 φ r 2 π 3 := By inspection P 16 := Recall
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w br φ r () 1 2 0 2 π P φ r n br φ r d 0 φ r φ r n br φ r d = s'=c Thus c'=-s w br 1 2 0 2 π P φ r 262 cos 8 φ r 2 π 3 d 0 φ rf φ r 262 cos 8 φ r 2 π 3 d = w br 1 2 262 8 sin 8 2 π 16 2 π 3 sin 0 2 π 3 262 8 sin 8 φ rf 2 π 3 0 sin 0 2 π 3
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hw9_solution - EE321 Spring 2008 HW#9 Problem 37 Note: I...

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