EE321 Spring 08
Homework 3
Problem 11 – UI Inductor Analysis
Consider the UI inductor design we did in class.
Using
1
=
dw
η
we get*:
•
N = 260 Turns
•
d = 8.4857 cm
•
g = 13.069 mm
•
w = 1.813 cm
•
aw = 21.5181 (mm)^2
•
ds = 8.94 cm
•
ws = 8.94 cm
In our design, we assumed that the permeability of the material was infinite.
Compute (a)
the inductance, (b) the flux density in the magnetic material, (c) the flux density in the air
gap, (d) the field intensity of the magnetic material, and (e) the field intensity in the air
gap if we assume that the relative permeability of the magnetic material is 2500.
Finally
compute (f) the percentage error between the desired inductance and the inductance that
we calculate assuming a relative permeability of 2500.
Assume the current is 40 A.
* These are a little different numbers than in class – remember I had accidently set
dw
η
to
something else.
Problem 12 – UI Inductor Analysis
Energy stored in a magnetic field may be expressed:
∫
⋅
=
volume
dv
E
H
B
2
1
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 Spring '08
 Staff
 Magnetism, Magnetic Field, Field Energy, UI Inductor Analysis

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